Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

In the given figure the capacitor circuit continues to infinity. The battery connected has e.m.f. equal to V. The potential difference between points 1 and 2 is V2, that between points 3 and 4 is V4 and so on; i.e., the potential difference becomes 12 after every step of the ladder. Find the ratio C1C2.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 2.00.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let the equivalent capacitance be C0. Even if we remove one ladder, the equivalent capacitance will remain C0.The potential drop across C1 in figure shown is V2.∴ q0C1=V2⇒q0=C1V2                     …(i)Also q0=C0V                                           …(ii)∴ C12=C0⇒C1=2C0                       …(iii)From the given circuit, C0=C0+C2C1C0+C2+C1⇒ C02+C2C0−C1C2=0Which gives, C0=−C2±C22+4C1C22Only positive sign is acceptable.∴ C0=−C2+C22+4C1C22∴ C12+C22=C22+4C1C22 ∵C12=C0C1+C22=C22+4C1C2C12=2C1C2⇒C1=2C2
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon