In the given figure the capacitor circuit continues to infinity. The battery connected has e.m.f. equal to V. The potential difference between points 1 and 2 is V2, that between points 3 and 4 is V4 and so on; i.e., the potential difference becomes 12 after every step of the ladder. Find the ratio C1C2.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 2.00.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let the equivalent capacitance be C0. Even if we remove one ladder, the equivalent capacitance will remain C0.The potential drop across C1 in figure shown is V2.∴ q0C1=V2⇒q0=C1V2 …(i)Also q0=C0V …(ii)∴ C12=C0⇒C1=2C0 …(iii)From the given circuit, C0=C0+C2C1C0+C2+C1⇒ C02+C2C0−C1C2=0Which gives, C0=−C2±C22+4C1C22Only positive sign is acceptable.∴ C0=−C2+C22+4C1C22∴ C12+C22=C22+4C1C22 ∵C12=C0C1+C22=C22+4C1C2C12=2C1C2⇒C1=2C2