First slide

P-N junction diode

Question

In the given figure, a diode D is connected to an external resistance R = 100 $Ω$ and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be

Moderate

A

20 mA
B

35 mA
C

30 mA
D

40 mA

Solution

The potential difference across the resistance R is
$V = 3.5 V - 0.5 V = 3 V$
By Ohm's law
The current in the circuit is
$I = \frac{V}{R} = \frac{3 V}{100 Ω}$
$= 3 \times 10^{- 2} A = 30 \times 10^{- 3} A = 30 mA$

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