First slide
P-N junction diode

In the given figure, a diode D is connected to an external resistance R = 100 Ω and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be



The potential difference across the resistance  R  is 

V=3.5 V-0.5 V=3 V

By Ohm's law

The current in the circuit is

I=VR=3 V100Ω

=3×10-2 A=30×10-3 A=30 mA

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