First slide

Second law

Question

In the given figure, a = 15 $m / s^{2}$ represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R=2.5 m at a given instant of time. The speed of the particle is

Moderate

A

5.7 m/s
B

6.2 m/s
C

4.5 m/s
D

5.0 m/s

Solution

$acos 30^{0} = a_{c} = \frac{v^{2}}{R}$
$\Rightarrow v^{2} = aR \times \frac{\sqrt{3}}{2} \Rightarrow v^{2} = 32.47 \Rightarrow v = 5.7 m / s$

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