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Q.

In the given figure, 15 ms-2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R = 2.5 m at a given instant of time. The speed of the particle is

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a

4.5 m s-1

b

5 m s-1

c

5.7 m s-1

d

6.2 m s-1

answer is A.

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Detailed Solution

Here, a=15 m s-2R = 2.5mFrom fig,ac=acos30°=15×32 m s-2 As we know, ac=v2R⇒v=acR∴v=15×32×2.5=5.69≃5.7 m s-1
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