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Questions  

In the given figure, 15 ms-2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R = 2.5 m at a given instant of time. The speed of the particle is 

 

 

a
4.5 m s-1
b
5 m s-1
c
5.7 m s-1
d
6.2 m s-1

detailed solution

Correct option is A

Here, a=15 m s-2R = 2.5mFrom fig,ac=acos30°=15×32 m s-2 As we know, ac=v2R⇒v=acR∴v=15×32×2.5=5.69≃5.7 m s-1

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Similar Questions

Statement -A : The net acceleration of a particle in circular motion is always along the radius of the circle towards the centre
Statement -B : The velocity vector of a particle at a point is always along the tangent to the path of the particle at that point


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