In the given figure magnetic field at the centre of ring (O) is 102T. Now it is bent through 90o about XX' axis, so that two semicircular parts are mutually perpendicular. Then find the value of magnetic field (in Tesla) at centre:

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102

answer is D.

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Detailed Solution

B=μ0i2RBnet =B12+B22=102T and B1=B2=B2=52T∴BNet=(52)2+(52)2=10T

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