In the given figure, a man of, true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string with a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass)

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The measured mass of man is Mm(M+m).

The acceleration of man is mg(M+m)

The acceleration of man is Mg(M+m)

The measured mass of man is M.

answer is A.

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Detailed Solution

Mg−T=Ma ........(i)T=ma ..........(ii)Solving Eqs. (i) and (i), a=MgM+mFBD of man,Mg−N=Ma⇒N=Mmg(M+m)

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