Q.
In the given figure, net magnetic field at O will be
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a
2μ0iπa4−π2
b
μ0i3πa4+π2
c
2μ0i3πa24+π2
d
2μ0i3πa4−π2
answer is B.
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Detailed Solution
Magnetic field at O due toPart (1):B1=0Part(2):B2=μ04π⋅πi(a/2)⊗ ( along −Z-axis) Part(3):B3=μ04π⋅i(a/2)(↓) ( along −Y-axis) Part (4): B4=μ04π⋅πi(3a/2)⊙ (along +Z-axis) Part (5):B5=μ04π⋅i(3a/2)(↓) ( along −Y-axis) B2−B4=μ04π⋅πia2−23=μ0i3a⊗B3+B5=μ04π⋅ia2+23=8μ0i12πa(↓) ( along −Y-axis )Hence, net magnetic fieldBnet=B2−B42+B3+B52=μ0i3πaπ2+4
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