As given in the figure, a series circuit connected across a 200 V, 60 Hz line consists of a capacitor of capacitive reactance 30ohm , a non-inductive resistor of 44 ohm , and a coil of inductive reactance 90ohm and resistance 36ohm . The power dissipated in the coil is (watt)

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answer is 0144.00.

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Detailed Solution

XC=30Ω , XL=90Ω , R=44+36=80ΩIrms=VrmsR2+XL-XC2⇒Irms=200(80)2+(90−30)2=2 A Power in coil =Irms2⁡R2=22×36=144 W

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