In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that θ is so small that tanθ≈sinθ then for equilibrium x is equal to
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a
q2L2πε0mg13
b
qL22πε0mg13
c
q2L24πε0mg13
d
q2L4πε0mg13
answer is A.
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Detailed Solution
In equilibriumFe=Tsinθ..............(i)mg=Tcosθ.............(ii)tanθ=Femg=q24πεox2×mg also tanθ≈sinθ=x/2L Hence x2L=q24πεox2×mg⇒ x3=2q2L4πεomg ⇒x=q2L2πεomg1/3