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Q.

Given is the graph between PVT and P for 1g of oxygen gas at two different temperatures T1 and T2, as shown in figure. Given, density of oxygen =1.427 kg m-3. The value of PV/T at the point A and the relation between T1 and T2 are respectively PVT JK−1

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a

0.259 J K-1 and T1

b

8.314 J mol-1 K-1 and T1>T2

c

0.259 J K-1 and T1>T2

d

4.28 g J K-1 and T1

answer is C.

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Detailed Solution

PV=nRT=mMRT​ where m= mass of the gas ​ and mM=n= number of moles⇒ ​PVT=nR= a constant for all values of P​ That is why ideally it is a straight line. ​∴ PVT=1 g32 g mol−1×8.31 J mol−1 K−1=0.259 J K−1​ Also, T1>T2Horizontal dotted line represents ideal gas. Curve 1 is closer to dotted line. A real gas is closer to ideal gas when it has high temperature.
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Given is the graph between PVT and P for 1g of oxygen gas at two different temperatures T1 and T2, as shown in figure. Given, density of oxygen =1.427 kg m-3. The value of PV/T at the point A and the relation between T1 and T2 are respectively PVT JK−1