Given is the graph between PVT and P for 1g of oxygen gas at two different temperatures T1 and T2, as shown in figure. Given, density of oxygen =1.427 kg m-3. The value of PV/T at the point A and the relation between T1 and T2 are respectively PVT JK−1
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a
0.259 J K-1 and T1
b
8.314 J mol-1 K-1 and T1>T2
c
0.259 J K-1 and T1>T2
d
4.28 g J K-1 and T1
answer is C.
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Detailed Solution
PV=nRT=mMRT where m= mass of the gas and mM=n= number of moles⇒ PVT=nR= a constant for all values of P That is why ideally it is a straight line. ∴ PVT=1 g32 g mol−1×8.31 J mol−1 K−1=0.259 J K−1 Also, T1>T2Horizontal dotted line represents ideal gas. Curve 1 is closer to dotted line. A real gas is closer to ideal gas when it has high temperature.
Given is the graph between PVT and P for 1g of oxygen gas at two different temperatures T1 and T2, as shown in figure. Given, density of oxygen =1.427 kg m-3. The value of PV/T at the point A and the relation between T1 and T2 are respectively PVT JK−1