Given A=2i^+3j^  andB=i^+j^ . The component of vector A along vector B is

The component of vector A along vector B=(A . B)B^  where B^=B→B   where B is the magnitude of vector B. now                (A . B)=(2i^+3j^). (i^+j^)                =2i^.i^+2i^.j^+3j^.i^+3j^.j^                =2+0+0+3=5Also       B=B→B=i^+j^i⏜+j⏜=i^+j^12+12=12(i^+j^)Thus the answer is 52(i^+j^)