Given A→=4i^+6j^ and B→=2i^+3j^. Which of the following is correct?

A→×B→=(4i^+6j^)×(2i^+3j^)=12(i^×j^)+12(j^×i^)                                             =12(i^×j^)−12(i^×j^)=0 Again, A→⋅B→=(4i^+6j^)⋅(2i^+3j^)=8+18=26 Again, |A→||B→|=16+364+9≠12 Also, B→=12A→⇒A→ and B→ are parallel and not antiparallel.