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Q.

For a given mass of a gas, the P-V graph for isothermal variations at temperatures T1 and T2 (kelvin) are shown in figure. Then

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a

T2=T1

b

T1>T2

c

T1

d

Information is incomplete to decide about temperatures

answer is C.

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Detailed Solution

For a given volume the pressure for T2 isothermal is more according to Charle's law at constant volumepressure is directly proportional to absolute temperature hence T1
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For a given mass of a gas, the P-V graph for isothermal variations at temperatures T1 and T2 (kelvin) are shown in figure. Then