Given mass number of gold = 197, density of gold = 19.7g cm–3, Avogadro’s number = 6 × 1023. The radius of the gold atom is approximately.

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1.5 x 10–8 m

1.5 x 10–9 m

1.5 x 10–10 m

1.5 x 10–12 m

answer is C.

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Detailed Solution

m = (vol)(density)A x mp=43πr3 x (den) ∴197 x 1.67 x 10-27 =43 x 3.14r3 x 19.7 x 103 ∴r3=1.67 x 34 x 3.14 x 10-30 ∴r3=4 x 10-30 ∴ r≅1.5 x 10-10m

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