Questions
Given mass number of gold = 197, density of gold = 19.7g cm–3, Avogadro’s number = 6 × 1023. The radius of the gold atom is approximately.
a
1.5 x 10–8 m
b
1.5 x 10–9 m
c
1.5 x 10–10 m
d
1.5 x 10–12 m
detailed solution
Correct option is C
m = (vol)(density)A x mp=43πr3 x (den) ∴197 x 1.67 x 10-27 =43 x 3.14r3 x 19.7 x 103 ∴r3=1.67 x 34 x 3.14 x 10-30 ∴r3=4 x 10-30 ∴ r≅1.5 x 10-10mTalk to our academic expert!
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