In the given network of capacitors as shown in figure, given that C1=C2=C3=400  pF  and  C4=C5=C6=200  pF. The effective capacitance of the circuit between X and Y is

Start with C3  and  C4 in parallel then C2 in series then C5 in parallel then  C1 in series, and finally C6 in parallel.∴Ceq=C3∥C4+C2∥C5+C1∥C6∴Ceq=C3+C4×C2C3+C4+C2+C5C1C3+C4×C2C3+C4+C2+C5+C1+C6  By substituting, C1=C2=C3=400pF&C4=C5=C6=200pF  We get, Ceq=410pF