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Questions  

In the given network, the potential at point O is (Given V0VS=18V)

a
9 V
b
780/47 V
c
680/43 V
d
none of these

detailed solution

Correct option is B

I=V0−VS1 = 18 AI1+I2+I3=I30−V03 + 40−V04 +50−V05 =18⇒  V0 = 780/47  V

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