First slide

Kcl

Question

In the given network, the potential at point O is (Given $V_{0} - V_{S} = 18 V)$

Moderate

A

9 V
B

780/47 V
C

680/43 V
D

none of these

Solution

$\begin{array}{l} I = \frac{V_{0} - V_{S}}{1} = 18 A \\ I_{1} + I_{2} + I_{3} = I \\ \frac{30 - V_{0}}{3} + \frac{40 - V_{0}}{4} + \frac{50 - V_{0}}{5} = 18 \\ \Rightarrow V_{0} = 780 / 47 V \end{array}$

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