In the given nuclear reaction A, B, C, D, E represents U $$238$$ $$92$$ →αTh A B →βPa C D →EU $$234$$ $$92$$

Correct option is 1A = 234, B = 90, C = 234, D = 91, E = β

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In the given nuclear reaction A, B, C, D, E represents
${}_{92}U^{238} \overset{α}{\to} {}_{B}{Th}^{A} \overset{β}{\to} {}_{D}{Pa}^{C} \overset{E}{\to} {}_{92}U^{234}$

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A = 234, B = 90, C = 234, D = 91, E = β

A = 234, B = 90, C = 238, D = 94, E = α

A = 238, B = 93, C = 234, D = 91, E = β

A = 234, B = 90, C = 234, D = 93,E = α

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detailed solution

Correct option is A

U 238 92 →αTh 234 90 →βPa 234 91 →E -1β0U 234 92

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In the given nuclear reaction A, B, C, D, E represents U 238 92 →αTh A B →βPa C D →EU 234 92

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Ready to Test Your Skills?

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In the given nuclear reaction A, B, C, D, E represents
${}_{92}U^{238} \overset{α}{\to} {}_{B}{Th}^{A} \overset{β}{\to} {}_{D}{Pa}^{C} \overset{E}{\to} {}_{92}U^{234}$