In the given nuclear reaction A, B, C, D, E represents 

${}_{92}\mathrm{U}^{238}\stackrel{\mathrm{\alpha }}{\to }{}_{\mathrm{B}}\mathrm{Th}^{\mathrm{A}}\stackrel{\mathrm{\beta }}{\to }{}_{\mathrm{D}}\mathrm{Pa}^{\mathrm{C}}\stackrel{\mathrm{E}}{\to }{}_{92}\mathrm{U}^{234}$

• A

  A = 234, B = 90, C = 234, D = 91, E = $\mathrm{\beta }$

• B

  A = 234, B = 90, C = 238, D = 94, E = $\mathrm{\alpha }$

• C

  A = 238, B = 93, C = 234, D = 91, E = $\mathrm{\beta }$

• D

  A = 234, B = 90, C = 234, D = 93,E = $\mathrm{\alpha }$