Questions
Given a number of capacitors labelled as C, V. Find the minimum number of capacitors needed to get an arrangement equivalent to Cnet, Vnet
detailed solution
Correct option is A
n in series ; m in paralleln=VnetV⇒Vnet=VnEffective capacitance of chain = C/nCnet=mCn⇒CnetC=mnTotal capacitors nm = CnetC x n x n=CnetC x VnetV2Talk to our academic expert!
Similar Questions
Two capacitors C1 and C2 having capacitance respectively are connected as shown in the figure. Initially C1 has charge 4 and C2 is uncharged. After long time closing the switch S :
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
