Q.
Given a number of capacitors labelled as C,V. Find the minimum number of capacitors needed to get an arrangement equivalent to Cnet, Vnet
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a
n=Cnet C×Vnet 2V2
b
n=CCnet×V2Vnet2
c
n=CCnet×VVnet
d
n=Cnet C×Vnet V
answer is A.
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Detailed Solution
F=σQ2ε0=Q22ε0A
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