First slide

Photo Electric Effect

Question

Given that a photon of light of wavelength 1000 $Å$ has an energy equal to 1.23 eV. When light of wavelength 5000 $Å$ and intensity I₀ falls on photoelectric cell, the saturation current is 0 . 40 x 10⁶amp. and the stopping potential is 1.36 V. Then the work-function is

Moderate

A

0.43 eV
B

1.10 eV
C

1.36 eV
D

2.47 eV

Solution

$hv = W + {eV}_{0} where e V_{o} = sto p p ing Potential W = hv - {eV}_{0} Incident wavelength = 5000 Å hv = energy of 5000 Å = 2 \times 1 \cdot 23 eV = 2 \cdot 46 eV {eV}_{0} = 1 \cdot 36 eV W = (2 \cdot 46 - 1 \cdot 36) = 1 \cdot 10 eV$

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