Given that a photon of light of wavelength 10,000 Å has an energy equal to 1.23 eV. When light of wavelength 5000 Å and intensity Io falls on a photoelectric cell,the saturation current is 0.40 x 10-6 A and the stopping potential is 1.36 V; if the intensity of light is made 4I0, then the saturation current will become
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a
0.40×1μA
b
0.40×2μA
c
0.40×4μA
d
0.40×8μA
answer is C.
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Detailed Solution
When intensity is increased from I0 to 4I0, i.e., four times, then the saturation current increases by a factor of 4, i.e., the saturation current becomes=4×0.40×10−6A