Given that a photon of light of wavelength 10,000 $\text{Å}$ has an energy equal to 1.23 eV. When light of wavelength 5000 $\text{Å}$ and intensity I_o falls on a photoelectric cell,
the saturation current is 0.40 x 10^-6 A and the stopping potential is 1.36 V; if the intensity of light is made 4I₀, then the stopping potential will become

• A

  $1.36\times 1 \mathrm{V}$

• B

  $1.36\times 2 \mathrm{V}$

• C

  $1.36\times 3 \mathrm{V}$

• D

  $1.36\times 4 \mathrm{V}$