Given that a photon of light of wavelength 10,000 Å has an energy equal to 1.23 eV. When light of wavelength 5000 Å and intensity Io falls on a photoelectric cell,the saturation current is 0.40 x 10-6 A and the stopping potential is 1.36 V; then the work function is

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0.43 eV

1.10 eV

1.36 eV

2.47 eV

answer is B.

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Detailed Solution

Since E∝1λ, so energy corresponding to 5000Å is E=2.46eV Now, hv−W=eVs or 2.46eV−W=1.36eVW=(2.46−1.36)eV=1.1eV

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