First slide

Dimensions of physical quantities

Question

Given that T stands for time period and l stands for the length of simple pendulum. If S is the acceleration due to gravrty, then which of the following statements about the relation $T^{2} = (l / g)$ is correct?

Moderate

A

It is correct both dimensionally as well as numerically.
B

It is neither dimensionally correct nor numerically.
C

It is dimensionally correct but not numerically.
D

It is numerically correct but not dimensionally.

Solution

The correct relation for time period of simple pendulum is $T = 2 π (l / g)^{1 / 2}$ . So the given relation is numerically incorrect as the factor of $2 π$ is missing. But it is correct dimensionally.

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