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Q.

In a given transistor, the emitter current is changed by 2.1 mA. This results in a change of 2 mA in the collector current and a change of 0.05 V in the emitter-base voltage. The input resistance in ohm  is:

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a

5000

b

3000

c

1000

d

500

answer is D.

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Detailed Solution

for transistor ∆ie=∆ic+∆ib ∆ib=∆ie-∆ic=2.1-2.0mA =0.1 mA input resistance = ∆vBE∆ib= 0.051×10-4= 500
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