First slide
Projectile motion
Question

For a given velocity, a projectile has the same range R for two angles of projection if t1 and t2 arc the times of flight in the two cases then 

Moderate
Solution

For same range angle of projection should be θ and, 90-θ

 So, time of flights t1=2usinθg and 

t2=2usin(90θ)g=2ucosθg

 By multiplying t1t2=4u2sinθcosθg2

t1t2=2gu2sin2θg=2Rgt1t2R

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