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Q.

A glass capillary tube is partially dipped in water vertically and water rises to a height h in the tube. The tube is now pushed down so that length of tube above the free surface of water is h/2. Then new angle of contact is

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a

0o

b

30o

c

60o

d

45o

answer is C.

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Detailed Solution

Initial angle of contact is  0o and final angle of contact is θ∴h=2Tcos0opgr  and h2=2Tcosθpgr∴h2=hcosθ⇒θ=600
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