Questions
A glass flask is filled up to a mark with 50 cc of mercury at 18°C. If the flask and contents are heated to 38°C, how much mercury will be above the mark ? ( for glass is 9 x 10-6/°C and coefficient of real expansion of mercury is 18 x 10-3/°C)
detailed solution
Correct option is C
Volume of mercury at 18°C = V0 = 50 ccVolume of mercury at 38°C = (V38)r =V01+γm⋅ΔtVolume of flask at 38∘C=V38f =V01+γfΔt∴Volume of mercury at 38°C above the mark =V01+γmΔt−V01+γfΔt=V0γm−γfΔt=5018×10−3−3×9×10−6(38−18)=0⋅153 ccTalk to our academic expert!
Similar Questions
A vessel having coefficient of cubical expansion contains liquid Of coefficient of real expansion rR up to certain level. When Vessel
Is heated, match column I and column II.
Column - I | Column - II | ||
a | p | liquid level rises continuously from beginning | |
b | q | liquid level falls continuously from beginning | |
c | r | liquid level remains same | |
d | s | liquid level first falls and then rises |
a | b | c | d | |
1 | s | r | q | p |
2 | s | r | p | q |
3 | q | r | s | p |
4 | r | q | p | s |
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