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Q.

A glass flask is filled up to a mark with 50 cc of mercury at 18oC. If the flask and contents are heated to 38oC, how much mercury will be above the mark (a for glass is 9×10−6/∘C and coefficient of real expansion of mercury is 180×10−6/∘C?

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a

0.85 cc

b

0.46 cc

c

0.153 cc

d

0.05 cc

answer is C.

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Detailed Solution

Volume of mercury at 18oCV0=50ccVolume of mercury at 38oCV38r=V01+γmΔθVolume of flask at 38oCV38f=V01+γfΔθVolume of mercury at 38oC above the tank =V01+γmΔθ−V01+γfΔθ=V0γm−γtΔθ=50180×10−6−3×9×10−6(38−18)=0.153cc

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A glass flask is filled up to a mark with 50 cc of mercury at 18oC. If the flask and contents are heated to 38oC, how much mercury will be above the mark (a for glass is 9×10−6/∘C and coefficient of real expansion of mercury is 180×10−6/∘C?