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Glass has refractive index μ with respect to air and the critical angle for a ray of light going from glass to air is θ. If a ray of light is incident from air on the glass with angle of incidence θ, the corresponding angle of refraction is 

a
sin−11μ
b
90∘
c
sin−11μ2
d
sin−11μ

detailed solution

Correct option is C

aμg=1sinθ⇒μ=1sinθ---(1)Now from Snell's law μ=sinisinr=sinθsinr⇒sinr=sinθμ---(2)From equation (i) and (ii) sinr=1μ2⇒r=sin−11μ2

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