Glass has refractive index μ with respect to air and the critical angle for a ray of light going from glass to air is θ. If a ray of light is incident from air on the glass with angle of incidence θ, the corresponding angle of refraction is

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sin−11μ

90∘

sin−11μ2

sin−11μ

answer is C.

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Detailed Solution

aμg=1sinθ⇒μ=1sinθ---(1)Now from Snell's law μ=sinisinr=sinθsinr⇒sinr=sinθμ---(2)From equation (i) and (ii) sinr=1μ2⇒r=sin−11μ2

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