First slide

Ray optics

Question

A glass prism has refracting angle $90^{0} .$ If angle of minimum deviation is $30^{0},$ refractive index of the material of the prism is

Easy

A

$\sqrt{2}$
B

$\sqrt{\frac{3}{2}}$
C

$\sqrt{3}$
D

$\sqrt{4}$

Solution

(2)
$μ = \frac{\sin \frac{1}{2} (δ_{m} + A)}{\sin \frac{A}{2}} = \frac{\sin (\frac{90^{0} + 30^{0}}{2})}{\sin (\frac{90^{0}}{2})} = \frac{\frac{\sqrt{3}}{2}}{1 / \sqrt{2}} = \sqrt{\frac{3}{2}}$

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