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A glass slab of thickness t = 3 cm, R.I. μ=32 is placed between the object O and the concave mirror of focal length f = 4.5 cm. It is observed that the image is formed at the object. If we withdraw the slab, the image will be formed at a distance of
 

a
10cm/11
b
30cm/11
c
80cm/11
d
90cm/11

detailed solution

Correct option is D

Apparent shift =31-23 cm=1 cm. Therefore x-1=2×4.5⇒x=10 cm.Therefore1v−110=−29       ⇒v=9011 cm

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