Questions
A glass sphere of radius 10 cm has refractive index . A is the position of a point object and B is its image. If A and B are equidistant from the surface of the sphere then separation between A and B is
detailed solution
Correct option is B
Since AP = BQ, the refracted ray MN inside the sphere, must be parallel to the diameter PQ. For first refraction at the surface of the sphere1α−1−AP=1.5−1+10⇒AP=20 cm∴Distance AB=AP+PQ+QB=20+20+20cm=60 cmTalk to our academic expert!
Similar Questions
A convex lens is at a distance of 10 cm from a convex mirror of focal length 10 cm as shown in figure. A beam of light parallel to the principal axis is incident on the tens. After refraction through the lens, reflection at the mirror and again refraction through the lens, the final emergent beam refraces the path of the incident beam then focal length of the lens is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests