Q.
A glass sphere of radius 10 cm has refractive index μ=1.5. A is the position of a point object and B is its image. If A and B are equidistant from the surface of the sphere then separation between A and B is
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a
40 cm
b
60 cm
c
50 cm
d
70 cm
answer is B.
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Detailed Solution
Since AP = BQ, the refracted ray MN inside the sphere, must be parallel to the diameter PQ. For first refraction at the surface of the sphere1α−1−AP=1.5−1+10⇒AP=20 cm∴Distance AB=AP+PQ+QB=20+20+20cm=60 cm
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