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Q.

The glycerine of density 1.25×103 kgm−3 is flowing through a conical tube with end radii 0.1 m and 0.04 m respectively. The pressure difference across the ends is 10 Nm-2. The rate of flow of glycerine through the tube is

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a

6.4×10−2 m3s−1

b

6.4×10−4 m3s−1

c

12.8×10−2 m3s−1

d

12.8×103 m3s−1

answer is B.

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Detailed Solution

Q=a1a22p1−p2ρa12−a22=πr12×πr222p1−p2ρπr122−πr222=πr12r222p1−p2ρr14−r24=227×(0.1)2×(0.04)22×101.25×103(0.1)4−(0.04)4=6.4×10−4 m3s−1
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