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45 gm of alcohol are needed to completely fill up a weight thermometer at 15°.C. The weight of alcohol which will overflow when the weight thermometer is heated to 33°C is (Take $γ_{a} = 121 \times 10^{- 5} /^{\circ} C$ )

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0.9 gm

0.96 gm

0.98 gm

none of these

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detailed solution

Correct option is B

γa=m15−m33m33T2−T1=45−m33m33(33−15)or 121×10−5=45−m33m33×18Solving, we get m33=45/(1⋅02178)gmWeight of alcohol overflowing =m15−m33=45−451⋅02178=45(1⋅02178−1)1⋅02178=45×0⋅021781⋅02178=0⋅96gm∴Weight of alcohol overflowing = 0.96 gm

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A vessel having coefficient of cubical expansion $γ_{g}$ contains liquid Of coefficient of real expansion r_R up to certain level. When Vessel
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