First slide

Third law

Question

A 20 gm bullet is shot horizontally and collides with a 1.98 kg block of wood. The bullet embeds in the block and the block slides along a rough horizontal surface for 1.5 m. If the coefficient of kinetic friction between the block and surface is 0.4, the original speed of the bullet is

Moderate

A

$200 \sqrt{3} m / s$
B

$100 \sqrt{3} m / s$
C

$100 m / s$ m/s
D

$200 m / s$

Solution

$b y c o n s r v a t i o n o f l i n e a r m o m e n t u m m v = (m + M) V 20 x 10^{- 3} v = (0.02 + 1.98) V V = 10^{- 2} v s t o p i n g d i s \tan c e S = \frac{V^{2}}{2 a} h e r e a = μ g V^{2} = 2 μ g s 10^{- 4} v^{2} = 2 (0.4) (10) (1.5) v = 200 \sqrt{3}$

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