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Q.

A 20 gm bullet is shot horizontally and collides with a 1.98 kg block of wood. The bullet embeds in the block and the block slides along a rough horizontal surface for 1.5 m. If the coefficient of kinetic friction between the block and surface is 0.4, the original speed of the bullet is

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a

2003 m/s

b

1003 m/s

c

100 m/sm/s

d

200 m/s

answer is A.

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Detailed Solution

by consrvation of linear momentum mv=(m+M)V 20x10-3v=(0.02+1.98)V V=10-2v stoping distance S= V22a here a=μg V2=2μgs 10-4 v2=2(0.4)(10)(1.5) v=2003
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