1 gm of steam at 1000C is mixed with 4 gm of ice at 00 C. Then final temperature of the mixture is ……Latent heat of fusion = 80 cal/gmLatent heat of evaporation = 540 cal/gm
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
72 oC
b
85 oC
c
64 oC
d
52 oC
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
1 x 1 x 100-θ+1 x 540=4 x 80+4 x 1 x θ-0⇒θ=640-3205 C 0=64 oC
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
1 gm of steam at 1000C is mixed with 4 gm of ice at 00 C. Then final temperature of the mixture is ……Latent heat of fusion = 80 cal/gmLatent heat of evaporation = 540 cal/gm