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Q.

1 gm of steam at 1000C is mixed with 4 gm of ice at 00 C. Then final temperature of the mixture is ……Latent heat of fusion = 80 cal/gmLatent heat of evaporation = 540 cal/gm

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a

72 oC

b

85 oC

c

64 oC

d

52 oC

answer is C.

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Detailed Solution

1 x 1 x 100-θ+1 x 540=4 x 80+4 x 1 x θ-0⇒θ=640-3205 C  0=64 oC
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1 gm of steam at 1000C is mixed with 4 gm of ice at 00 C. Then final temperature of the mixture is ……Latent heat of fusion = 80 cal/gmLatent heat of evaporation = 540 cal/gm