First slide

Questions based on phase change

Question

5 gm of steam at 100°C is passed into 6 gm of ice at 0°C. If the latent heat of steam and ice in cal per gm are 540 and 80 respectively, then the final temperature is

Moderate

A

0°C
B

100°C
C

50°C
D

30°C

Solution

Let us assume here that resulting temperature=100°C
$∴ Q_{1}$ heat supplied by 5 gm of steam if it was to condense totally into water at 100°C
= 5 X 540= 2700 cal
and Q₂ = heat required to melt 6 gm of ice at 0°C
into water at $0^{o}$ C + heat required to raise the
temperature of 6 gm of water from 0°C to 100°C
= 480 + 600 = 1080 cal
As $Q_{1}$ > $Q_{2}$ , hence whole of steam will not condense. If m' gm be the mass of steam which condenses into water at 100°C , then m' 540= 1080
$∴$ m'= 2 gm

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