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80 gm of water at 30°C is poured on a large block of ice at 0°C. The mass of ice that melts is
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a
30 gm
b
80 gm
c
150 gm
d
1600 gm
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Correct option is A
Since, the block of ice at 0°C is large, the whole of ice will not melt, hence final temperature is 0°C .∴Q1 = heat given by water in cooling upto 0°C=msΔθ=80×1×(30−0)= 2400 calIf m gm be the mass of ice melted, thenQ2 = mLF = m x 80Now, Q2 = Q1m x 80 = 2400 or m = 30 gm.Similar Questions
10 g of ice at -20°C is dropped into a calorimeter containing 10 g of water at l 0°C; the specific heat _of water is twice that of ice . When equilibrium is reached,· the calorimeter will contain:
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