Questions
80 gm of water at 30oC is poured on a large block of ice at 0oC. The mass of ice that melts is
detailed solution
Correct option is A
Since, the block of ice at 0oC is large, the whole of ice will not melt, hence final temperature is 0oC .∴Q1 = heat given by water in cooling upto 0oC=msΔθ=80×1×(30−0)= 2400 calIf m gm be the mass of ice melted, thenQ2=mLF=m×80 Now, Q2=Q1m x 80 = 2400 or m = 30 gm.Talk to our academic expert!
Similar Questions
A piece of ice falls from a height h, so that it melts completely. Only one-quarter of the heat produced is absorbed by the ice and all energy of ice gets converted into heat during its fall. The value of h is (Take, latent heat of ice is 3.4 X 105 ]/kg and g = 10 N/kg)
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