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300 grams of water at 25C  is added to 100 grams of ice at 0C , the final temperature of the mixture is 

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By Expert Faculty of Sri Chaitanya
a
−53  ∘C
b
−52  ∘C
c
-5oC
d
0∘C
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detailed solution

Correct option is D

Wateramount of heat lost by water is dQ1=mSdθ here m is mass of water ; S is specific heat of water; dθ is change in temperature of water when water looses its temperature from 250C to 00C, amount of heat lost is  dQ1 dQ1=300×1×25=7500  calorieFor Iceamount of heat required to convert from ice to water is dQ2=mL where m is mass of ice ; L = latent heat of fusion of ice=80 cal g-1 dQ2=100×80=8000  caldQ2>dQ1i.e., Heat required is greater than heat availableStill ice remains= 0oC


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