Questions

300 grams of water at ${25}^{\circ }\text{C}$  is added to 100 grams of ice at ${0}^{\circ }\text{C}$ , the final temperature of the mixture is

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
−53  ∘C
b
−52  ∘C
c
-5oC
d
0∘C
NEW

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is D

Wateramount of heat lost by water is dQ1=mSdθ here m is mass of water ; S is specific heat of water; dθ is change in temperature of water when water looses its temperature from 250C to 00C, amount of heat lost is  dQ1 dQ1=300×1×25=7500  calorieFor Iceamount of heat required to convert from ice to water is dQ2=mL where m is mass of ice ; L = latent heat of fusion of ice=80 cal g-1 dQ2=100×80=8000  caldQ2>dQ1i.e., Heat required is greater than heat availableStill ice remains= 0oC

Similar Questions

A bullet of mass 5g , Travelling with a speed of  210 m/s , strikes a fixed wooden target . One half its kinetic energy is converted in to heat in the bullet while the other half is converted in to heat in the wood. The rise of temperature of the bullet if the specific heat of the material is 0.030 cal/$\left({\text{g-}}^{\text{0}}\text{C}\right)\left(1cal=4.2×{10}^{7}\text{ergs}\right)$ close to:

Get your all doubts cleared from
Sri Chaitanya experts

+91