$$300$$ grams of water at $$25$$∘C is added to $$100$$ grams of ice at $$0$$∘C , the final temperature of the mixture is

Question

$$300$$ grams of water at $$25$$∘C  is added to $$100$$ grams of ice at $$0$$∘C , the final temperature of the mixture is

Infinity Learn · Accepted Answer

Wateramount of heat lost by water is $$dQ1=mSd$$θ here m is mass of water ; S is specific heat of water; dθ is change in temperature of water when water looses its temperature from $$250C$$ to $$00C$$, amount of heat lost is  $$dQ1$$ $$dQ1=300$$×$$1$$×$$25=7500$$  calorieFor Iceamount of heat required to convert from ice to water is $$dQ2=mL$$ where m is mass of ice ; L $$=$$ latent heat of fusion of $$ice=80$$ cal $$g-1$$ $$dQ2=100$$×$$80=8000$$  $$caldQ2$$>$$dQ1i$$.e., Heat required is greater than heat availableStill ice $$remains=$$ $$0oC$$

300 grams of water at $25^{\circ} C$ is added to 100 grams of ice at $0^{\circ} C$ , the final temperature of the mixture is

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

300 grams of water at 25∘C is added to 100 grams of ice at 0∘C , the final temperature of the mixture is

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

300 grams of water at $25^{\circ} C$ is added to 100 grams of ice at $0^{\circ} C$ , the final temperature of the mixture is