First slide

Calorimetry

Question

80 grams of water at 30° C are poured on a large block of ice at 0° C. The mass of ice melted is:(Latent Heat of fusion of ice =80 cal $g^{- 1}$ )

Moderate

A

30 grams
B

80 grams
C

160 grams
D

60 grams

Solution

from principle of method of mixtures
$\begin{array}{rcl} h e a t l o s t b y w a t e r & = & h e a t g a i n e d b y i c e \\ m s ∆ T & = & m_{i c e m e l t e d} L - - - (1) \\ h e r e s i s s p e c i f i c h e a t o f w a t e r & = & 1 \\ m i s m a s s o f w a t e r & = & 80 g (g i v e n) \\ ∆ T i s c h a n g e i n t e m p e r a t u r e & = & 30 - 0 = 30^{0} C \\ L i s l a t e n t h e a t o f f u s i o n o f i c e & = & 80 c a l o r i e g^{- 1} \\ s u b s t i t u t e a b o v e v a l u e s i n e q u a t i o n (1) \\ 80 (1) (30) & = & m (80) \\ m a s s o f i c e m e l t e d & = & 30 g \end{array}$

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