Q.

80 grams of water at 30° C are poured on a large block of ice at 0° C. The mass of ice melted is:(Latent Heat of fusion of ice =80 cal g-1)

Moderate

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By Expert Faculty of Sri Chaitanya

30 grams

80 grams

160 grams

60 grams

answer is 1.

(Detailed Solution Below)

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Detailed Solution

from principle of method of mixturesheat lost by water = heat gained by icems ∆T=mice meltedL---(1)here s is specific heat of water =1m is mass of water= 80g (given)∆T is change in temperature= 30-0=300CL is latent heat of fusion of ice =80 calorie g-1 substitute above values in equation (1)80(1)(30)=m(80)mass of ice melted = 30 g

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