The graph of alternating current versus time is shown in figure. The average value for the positive half cycle, is

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I03

2I0π

5I08

I02

answer is D.

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Detailed Solution

Iavg=∫0T/2 Idt∫0T/2 dt=I02. Area of the triangle divided by the time interval (T/2) will also provide the average value of the signal.

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