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Questions  

The graph of alternating current versus time is shown in figure. The average value for the positive half cycle, is  

a
I03
b
2I0π
c
5I08
d
I02

detailed solution

Correct option is D

Iavg=∫0T/2 Idt∫0T/2 dt=I02. Area of the triangle divided by the time interval (T/2) will also provide the average value of the signal.

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