Questions
The graph of alternating emf versus time is shown in the figure. The average of this alternating emf in the first one-half cycle will be
a
V0/3
b
V0/2
c
4V0/5
d
5V0/8
detailed solution
Correct option is B
Vavg=∫0T/2 Vdt∫T/2 dt.Area of the triangle divided by the time interval (T/2) will also provide the average value of the signal.Talk to our academic expert!
Similar Questions
The graph of alternating current versus time is shown in figure. The average value for the positive half cycle, is
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