Question

The graph between $\sqrt{E}$ and $\frac{1}{p}$ is ( E = kinetic energy and p = momentum)

Moderate

Solution

$P = \sqrt{2 mE}$ it is clear that $P \propto \sqrt{E}$
So the graph between P and $\sqrt{E}$ will be straight line.
but graph between $\frac{1}{P}$ and $\sqrt{E}$ will be hyperbola

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