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Q.

The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s. When the distance covered by the body is 4 m, its kinetic energy would be (in J)

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answer is 10.

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Detailed Solution

Initial K.E. of the body = 12mv2=12×25×4=50 JWork done against resistive force= Area between F-x graph = 12×4×20=40JFinal K.E. = Initial K.E. – Work done against resistive force = 50−40=10 J

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The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s. When the distance covered by the body is 4 m, its kinetic energy would be (in J)