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The graph between the stopping potential (V₀) and $(\frac{1}{λ})$ is shown in the figure. $ϕ_{1}, ϕ_{2} and ϕ_{3}$ are work functions. Which of the following is/are correct?

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ϕ1:ϕ2:ϕ3=1:2:4

ϕ1:ϕ2:ϕ3=4:2:1

tan⁡θ∝hce

ultraviolet can be used to emit photoelectrons from metal 2 and metal 3 only

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detailed solution

Correct option is A

eV=hcλ−ϕ when V=0, ⇒ϕ=hcλ ∴ϕ1:ϕ2:ϕ3=1λ1:1λ2:1λ3=0.001:0.002:0.004=1:2:4 ⇒ V=hceλ−ϕe …(1)slope=m=hce=tan⁡θ1λ01=0.001nm−1⇒λ01=10.001=1000nm Also, 1λ02=0.002nm−1⇒λ02=500nm and λ03=250nm

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The graph between the stopping potential (V0) and 1λ is shown in the figure. ϕ1,ϕ2 and ϕ3 are work functions. Which of the following is/are correct?

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The graph between the stopping potential (V₀) and $(\frac{1}{λ})$ is shown in the figure. $ϕ_{1}, ϕ_{2} and ϕ_{3}$ are work functions. Which of the following is/are correct?