The graph between the stopping potential (V0) and 1λ is shown in the figure. ϕ1,ϕ2 and ϕ3 are work functions. Which of the following is/are correct?

eV=hcλ−ϕ when V=0, ⇒ϕ=hcλ ∴ϕ1:ϕ2:ϕ3=1λ1:1λ2:1λ3=0.001:0.002:0.004=1:2:4 ⇒ V=hceλ−ϕe …(1)slope=m=hce=tan⁡θ1λ01=0.001nm−1⇒λ01=10.001=1000nm Also, 1λ02=0.002nm−1⇒λ02=500nm and λ03=250nm