First slide

Temperature and heat-thermal properties of matter

Question

A graph is drawn between centigrade & Fahrenheit scales such that centigrade on Y-axis and Fahrenheit on X-axis, then slope of the graph

Easy

A

$\frac{9}{5}$
B

$\frac{4}{5}$
C

$\frac{5}{9}$
D

$\frac{5}{4}$

Solution

intercept on fahrenheit axis is 32F and intercept on centigrade axis is -17.78C
$∴$ $\frac{c}{100} = \frac{F - 32}{180} C = \frac{5 F}{9} - 160 s l o p e o f t h e g r a p h i s \frac{5}{9}$

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