Q.

The graph drawn between change in length and varying load W is a straight line starting from origin. Cross-sectional area of the wire is 10−6m2  and length of wire is 10cm. Slope of the curve is 10−420 Young’s modulus will be:

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a

2×1010Nm−2

b

1011Nm−2

c

3×10−11Nm−2

d

None of these

answer is A.

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Detailed Solution

Y=FlAe; slope= eFY=2010−4×0.110−6=2×1010  N/m2
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The graph drawn between change in length and varying load W is a straight line starting from origin. Cross-sectional area of the wire is 10−6m2  and length of wire is 10cm. Slope of the curve is 10−420 Young’s modulus will be: