The graph shown below gives the extension (ΔL) of a wire of length 1 m suspended from the top of a roof at one end with a load w connected to the other end. If the cross-sectional area of the wire is 10-6 m2, calculate the Young's modulus of the material of the wire.
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a
2×1011Nm−2
b
2×10−11Nm−2
c
3×10−12Nm−2
d
2×10−13Nm−2
answer is A.
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Detailed Solution
We have, ΔLw=(4−1)×10−480−20=10−420Elongation, ΔL=wLAY⇒ Y=LAΔLwΔYoung's modulus, Y=110−6×2010−4=2×1011Nm−2