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Questions  

The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that

a
The force is zero at time 3T/4
b
The velocity is maximum at time T/2
c
The acceleration is maximum at time T
d
The P.E. is equal to total energy at time T/2

detailed solution

Correct option is D

At time T2; v=0, KE=0Total energy = Potential energy.

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The acceleration a of a particle undergoing S.H.M. is shown in the figure. Which of the labelled points corresponds to the particle being at – xmax 


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