Q.
The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that
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a
The force is zero at time 3T/4
b
The velocity is maximum at time T/2
c
The acceleration is maximum at time T
d
The P.E. is equal to total energy at time T/2
answer is D.
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Detailed Solution
At time T2; v=0, KE=0Total energy = Potential energy.
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