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The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that

The force is zero at time 3T/4
The velocity is maximum at time T/2
The acceleration is maximum at time T
The P.E. is equal to total energy at time T/2

detailed solution

Correct option is D

At time T2; v=0, KE=0Total energy = Potential energy.

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The acceleration a of a particle undergoing S.H.M. is shown in the figure. Which of the labelled points corresponds to the particle being at – xmax 

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